document.write( "Question 24564: Factoring Polynomials. I had a horrible Algebra II teacher last year and learned almost nothing that i was supposed to because of it. I dont think I am very good at factoring. This is for College Algebra. I am dually enrolled in high school and a community college. The directions say to factor out, relative to the integers, all factors common to all terms. The problem is..
\n" ); document.write( "2w(y-2z)-y(y-2Z) I went ahead and simplified the problem, believing that to be the right thing to do. I got..2wy-4wz-y^2+2yz The answer is..(2w-x)(y-2z)
\n" ); document.write( "Thank you so much. I absolutely must learn this stuff. Any correct explanation will be taken to heart. \n" ); document.write( "

Algebra.Com's Answer #13078 by Earlsdon(6294) $\"\"$ $\"About$

You can put this solution on YOUR website!
Well, your answer is almost correct...except for a small typo. You have an x in the answer when there is no x in the original expression. Here are the steps:
\n" ); document.write( "Factor:
\n" ); document.write( " $\"2w%28y-2z%29-y%28y-2z%29\"$ It is not neccesary to simplify as you did because, if you look at the expression, you will see that each term has a common factor of (y-2z) and this, of course, can be factored out.
\n" ); document.write( " $\"%28y-2z%29%282w-y%29\"$ ...and there you have it! \n" ); document.write( "

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