document.write( "Question 175658: Please help me solve this equation: Pat invested a total of $3,000. Part of the money yields 10 percent interest
\n" ); document.write( "per year, and the rest yields 8 percent interest per year. If the total yearly
\n" ); document.write( "interest from this investment is $256, how much did Pat invest at 10 percent
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Algebra.Com's Answer #130758 by Mathtut(3670)\"\" \"About 
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let x and y be the amounts invested at 10% and 8%
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\n" ); document.write( "x+y=3000........eq 1
\n" ); document.write( ".1x+.08y=256....eq 2
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\n" ); document.write( "rewrite eq 1 to x=3000-y and plug that value into eq2
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\n" ); document.write( ".1(3000-y)+.08y=256
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\n" ); document.write( "300-.1y+.08y=256
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\n" ); document.write( "-.02y=-44
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\n" ); document.write( "$\"highlight%28y=2200%29\"amount invested at 8%
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\n" ); document.write( "$\"highlight%28x=3000-2200=800%29\"amount invested at 10%
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