document.write( "Question 175629This question is from textbook Algebra 1
\n" ); document.write( ": If the digits of a two-digit positive interger are reversed, the result is 6 less than twice the original numder. Find all such intergers for which this is true.\r
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Algebra.Com's Answer #130725 by solver91311(24713)\"\" \"About 
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Let the tens digit be represented by \"d%5Bt%5D\" and the ones digit be represented by \"d%5Bo%5D\". That means you can represent any two digit positive number by \"10d%5Bt%5D+%2B+d%5Bo%5D\" if you restrict \"d%5Bt%5D\" and \"d%5Bo%5D\" to the set {0, 1, 2, 3, 4, 5, 6, 7, 8, 9}.\r
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\n" ); document.write( "\n" ); document.write( "If our original number is \"10d%5Bt%5D+%2B+d%5Bo%5D\" then the number with reversed digits is \"10d%5Bo%5D+%2B+d%5Bt%5D\". Then the conditions of the problem give us:\r
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\n" ); document.write( "\n" ); document.write( "\"2%2810d%5Bt%5D+%2B+d%5Bo%5D%29+-+6+=+10d%5Bo%5D+%2B+d%5Bt%5D\"\r
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\n" ); document.write( "\n" ); document.write( "Simplify and solve for \"d%5Bt%5D\"\r
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\n" ); document.write( "\n" ); document.write( "\"20d%5Bt%5D+%2B+2d%5Bo%5D+-+6+=+10d%5Bo%5D+%2B+d%5Bt%5D\"\r
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\n" ); document.write( "\n" ); document.write( "\"19d%5Bt%5D+=+8d%5Bo%5D+%2B+6\"\r
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\n" ); document.write( "\n" ); document.write( "\"d%5Bt%5D+=+%288d%5Bo%5D+%2B+6%29%2F19\"\r
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\n" ); document.write( "\n" ); document.write( "Now remember that both \"d%5Bt%5D\" and \"d%5Bo%5D\" are restricted to the set {0, 1, 2, 3, 4, 5, 6, 7, 8, 9}. That means that we have to find which of the given set of numbers, when substituted for \"d%5Bo%5D\", yield \"d%5Bt%5D\" also an element of the given set. We know that since the denominator is 19 and there are only ten consecutive integer possibilities, we have at most 1 solution.\r
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\n" ); document.write( "\n" ); document.write( "We can also see that \"8d%5Bo%5D+%2B+6\" must be an integer multiple of 19.\r
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\n" ); document.write( "\n" ); document.write( "The first five integer multiples of 19 are 19, 38, 57, 76, and 95. So:\r
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\n" ); document.write( "\n" ); document.write( "\"8d%5Bo%5D+%2B+6+=+19\"\"8d%5Bo%5D+=+12\"\"d%5Bo%5D\" not an integer.\r
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\n" ); document.write( "\n" ); document.write( "\"8d%5Bo%5D+%2B+6+=+38\"\"8d%5Bo%5D+=+32\"\"red%28d%5Bo%5D+=+4%29\" IS an integer. This is our solution, but let's continue just to make sure.\r
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\n" ); document.write( "\n" ); document.write( "\"8d%5Bo%5D+%2B+6+=+57\"\"8d%5Bo%5D+=+51\"\"d%5Bo%5D\" not an integer.\r
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\n" ); document.write( "\n" ); document.write( "\"8d%5Bo%5D+%2B+6+=+76\"\"8d%5Bo%5D+=+70\"\"d%5Bo%5D\" not an integer.\r
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\n" ); document.write( "\n" ); document.write( "\"8d%5Bo%5D+%2B+6+=+95\"\"8d%5Bo%5D+=+89\"\"d%5Bo%5D\" not an integer AND \"d%5Bo%5D+%3E+9\" so we can stop looking.\r
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\n" ); document.write( "\n" ); document.write( "Now we know the ones digit is 4, so using \"d%5Bt%5D+=+%288%284%29+%2B+6%29%2F19+=+38%2F19+=+2\" we know the tens digit is 2.\r
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\n" ); document.write( "\n" ); document.write( "The only positive two-digit integer that satisfies the given conditions is 24.\r
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\n" ); document.write( "\n" ); document.write( "Check the answer:\r
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\n" ); document.write( "\n" ); document.write( "2 times 24 is 48 which is 6 more than 42 which is 24 with the digits reversed. Checks.\r
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\n" ); document.write( "\n" ); document.write( "By the way, the word is integer, not interger.\r
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