document.write( "Question 175615: A clerk was asked to change a $10 bill. She returned 9 more dimes than nickels and twenty-one more quarters than dimes. How many coins of each did she return? \n" ); document.write( "
Algebra.Com's Answer #130721 by EMStelley(208)![]() ![]() You can put this solution on YOUR website! Call the number of nickels n. Then she returned n+9 dimes and (n+9)+21 quarters. The dollar amounts of each can be represented by 0.05n, 0.10(n+9) and 0.25((n+9)+21). So you need to solve\r \n" ); document.write( "\n" ); document.write( "0.05n + 0.10(n+9) + 0.25((n+9)+21) = 10.00 \n" ); document.write( " |