document.write( "Question 175629This question is from textbook Algebra 1
\n" ); document.write( ": If the digits of a two-digit positive interger are reversed, the result is 6 less than twice the original numder. Find all such intergers for which this is true.\r
\n" ); document.write( "\n" ); document.write( "How do you figure this out?
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Algebra.Com's Answer #130710 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Here's how to find the value of a number if
\n" ); document.write( "you are given the digits:
\n" ); document.write( "Let the 10s digit = \"m\"
\n" ); document.write( "Let the 1s digit = \"n\"
\n" ); document.write( "The value of the number is \"10m+%2B+n\"
\n" ); document.write( "Given:
\n" ); document.write( "\"10n+%2B+m+=+2%2A%2810m+%2B+n%29+-+6\"
\n" ); document.write( "\"10n+%2B+m+=+20m+%2B+2n+-+6\"
\n" ); document.write( "\"19m+-+6+=+8n\"
\n" ); document.write( "The key to going on from here is to realize
\n" ); document.write( "that \"m\" and \"n\" are single digits
\n" ); document.write( "and can only be 0 - 9.
\n" ); document.write( "\"m\" can't be \"0\", you can't start a 2-digit
\n" ); document.write( "number with \"0\". I'll find \"m\" and
\n" ); document.write( "solve for \"n\"
\n" ); document.write( "\"19m+-+6+=+8n\"
\n" ); document.write( "----------
\n" ); document.write( "m -- n
\n" ); document.write( "1 -- 13/8 not a digit
\n" ); document.write( "2 -- 4
\n" ); document.write( "3 -- 51/8 not a digit
\n" ); document.write( "4 -- 35/4 not a digit
\n" ); document.write( "5 -- 89/8 not a digit
\n" ); document.write( "6 -- 27/2 not a digit
\n" ); document.write( "7 -- 127/8 not a digit
\n" ); document.write( "8 -- 73/4 not a digit
\n" ); document.write( "9 -- 165/8 not a digit
\n" ); document.write( "The only number found is 24
\n" ); document.write( "check:
\n" ); document.write( "\"10n+%2B+m+=+2%2A%2810m+%2B+n%29+-+6\"
\n" ); document.write( "\"10%2A4+%2B+2+=+2%2A%2810%2A2+%2B+4%29+-+6\"
\n" ); document.write( "\"42+=+2%2A24+-+6\"
\n" ); document.write( "\"42+=+42\"
\n" ); document.write( "OK
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