document.write( "Question 175626: Find the additive inverse of each number\r
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Algebra.Com's Answer #130704 by solver91311(24713)\"\" \"About 
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The additive inverse of any number \"s\" is that number when added to the original number results in \"0\", in other words \"-s\". That is because \"s+%2B+%28-s%29+=+0\" for all \"s\".\r
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\n" ); document.write( "\n" ); document.write( "In order to add two complex numbers, you add the real parts and then add the real coefficients of the imaginary parts, thus:\r
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\n" ); document.write( "\n" ); document.write( "\"%28a+%2B+bi%29+%2B+%28c+%2B+di%29+=+%28%28a+%2B+c%29+%2B+%28b+%2B+d%29i%29\"\r
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\n" ); document.write( "\n" ); document.write( "Hence, if you are trying to find the additive inverse of a complex number you need to find the additive inverse of the real part and the additive inverse of the coefficient of the imaginary part.\r
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\n" ); document.write( "\n" ); document.write( "Problem 1. \"+3+-+7i\"\r
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\n" ); document.write( "\n" ); document.write( "The additive inverse of \"3\" is \"-3\" and the additive inverse of \"-7\" is \"7\" so the additive inverse of \"+3+-+7i\" must be \"-3+%2B+7i\".\r
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\n" ); document.write( "\n" ); document.write( "Do the other problem the same way.
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