document.write( "Question 175616: A club treasurer has $28.45 consisting of nickels, dimes, and quarters. She has 9 more nickels than dimes and three times as many dimes as quarters. How many does she have of each coin? \n" ); document.write( "
Algebra.Com's Answer #130701 by ankor@dixie-net.com(22740)\"\" \"About 
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treasurer has $28.45 consisting of nickels, dimes, and quarters.
\n" ); document.write( " She has 9 more nickels than dimes and three times as many dimes as quarters.
\n" ); document.write( " How many does she have of each coin?
\n" ); document.write( ":
\n" ); document.write( "Write an equation for each statement:
\n" ); document.write( ":
\n" ); document.write( "\"treasurer has $28.45 consisting of nickels, dimes, and quarters.\"
\n" ); document.write( ".05n + .10d + .25q = 28.45
\n" ); document.write( ":
\n" ); document.write( " \"She has 9 more nickels than dimes\"
\n" ); document.write( "n = d + 9
\n" ); document.write( ":
\n" ); document.write( "\" and three times as many dimes as quarters.\"
\n" ); document.write( "d = 3q
\n" ); document.write( "or we can write it:
\n" ); document.write( "q = \"1%2F3\"d
\n" ); document.write( ":
\n" ); document.write( " How many does she have of each coin?
\n" ); document.write( ":
\n" ); document.write( "Using the 1st equation substitute:
\n" ); document.write( "(d+9) for n
\n" ); document.write( "\"1%2F3\"d for q
\n" ); document.write( ".05(d+9) + .10d + .25(\"1%2F3\"d) = 28.45
\n" ); document.write( ".05d + .45 + .10d + \".25%2F3\"d = 28.45
\n" ); document.write( ".15d + \".25%2F3\"d = 28.45 - .45
\n" ); document.write( ".15d + \".25%2F3\"d = 28.00
\n" ); document.write( "Multiply equation by 3 to get rid of the denominator
\n" ); document.write( ".45d + .25d = 84
\n" ); document.write( ".70d = 84
\n" ); document.write( "d = \"84%2F.7\"
\n" ); document.write( "d = 120 dimes
\n" ); document.write( ":
\n" ); document.write( "Find nickels:
\n" ); document.write( "n = 120 + 9
\n" ); document.write( "n = 129 nickels
\n" ); document.write( ":
\n" ); document.write( "Find quarters:
\n" ); document.write( "q = \"1%2F3\"*120
\n" ); document.write( "q = 40 quarters
\n" ); document.write( ";
\n" ); document.write( ":
\n" ); document.write( "Check solutions in the 1st equation:
\n" ); document.write( ".05(129) + .10(120) + .25(40) =
\n" ); document.write( "6.45 + 12.00 + 10.00 = 28.45; confirms our solutions\r
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