document.write( "Question 24555: what is the center of the circle x^2 + 4x + y^2 + 2y - 9 = 0? \n" ); document.write( "
Algebra.Com's Answer #13070 by kev82(151)\"\" \"About 
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Hi,\r
\n" ); document.write( "\n" ); document.write( "The general equation of a circle as I'm sure you know is \"%28x-a%29%5E2%2B%28y-b%29%5E2=r%5E2\" where (a,b) is the centerpoint and r is the radius. We can make your equation look like this one by completing the square.\r
\n" ); document.write( "\n" ); document.write( "Firstly we're looking for the value of a such that \"%28x-a%29%5E2=x%5E2%2B4x\" You can either just guess that \"a=-2\" or expand and compare coefficients. But \"%28x-%28-2%29%29%5E2=x%5E2%2B4x%2B4\" So \"x%5E2%2B4x=%28x%2B2%29%5E2-4\"\r
\n" ); document.write( "\n" ); document.write( "Doing the same for y, we get \"y%5E2%2B2y=%28y%2B1%29%5E2-1\" Finally substituting into the equation we get\r
\n" ); document.write( "\n" ); document.write( "\"%28x%2B2%29%5E2+%2B+%28y%2B1%29%5E2+-4+-1+-9=0\"\r
\n" ); document.write( "\n" ); document.write( "So, in the standard form for a circle we get\r
\n" ); document.write( "\n" ); document.write( "\"%28x%2B2%29%5E2+%2B+%28y%2B1%29%5E2+=14\"\r
\n" ); document.write( "\n" ); document.write( "So we can read off from this that the circle is centered at (-2,-1) with a radius of \"sqrt%2814%29\"\r
\n" ); document.write( "\n" ); document.write( "Hope that helps,
\n" ); document.write( "Kev
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