document.write( "Question 175614: Sally has seven times as many dimes as nickels. Their value is $3.00. How many nickels does she have? \n" ); document.write( "
Algebra.Com's Answer #130693 by solver91311(24713)\"\" \"About 
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Number of nickels: \"n\"\r
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\n" ); document.write( "\n" ); document.write( "Number of dimes: \"d\"\r
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\n" ); document.write( "\n" ); document.write( "We know that \"d+=+7n\" because Sally has seven times as many dimes as nickels.\r
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\n" ); document.write( "\n" ); document.write( "Each of Sally's nickels is worth 5 cents, so the value, in cents, of all of Sally's nickels is \"5n\". Likewise, the value, in cents, of all of Sally's dimes is \"10d\".\r
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\n" ); document.write( "\n" ); document.write( "We know that the total value of Sally's coins is $3.00, but we can also say that the total value of her coins is 300 cents. Now we can write:\r
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\n" ); document.write( "\n" ); document.write( "\"5n+%2B+10d+=+300\"\r
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\n" ); document.write( "\n" ); document.write( "But since we also know that \"d+=+7n\", we can substitute \"7n\" for \"d\":\r
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\n" ); document.write( "\n" ); document.write( "\"5n+%2B+10%287n%29+=+300\"\r
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\n" ); document.write( "\n" ); document.write( "Solving:\r
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\n" ); document.write( "\n" ); document.write( "\"5n+%2B+70n+=+300\"\r
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\n" ); document.write( "\n" ); document.write( "\"75n+=+300\"\r
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\n" ); document.write( "\n" ); document.write( "\"n+=+300%2F75+=+4\"\r
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\n" ); document.write( "\n" ); document.write( "Therefore Sally has 4 nickels.\r
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\n" ); document.write( "\n" ); document.write( "Check: If Sally has 4 nickels, she must have \"7+%2A+4+=+28\" dimes. 28 dimes are worth $2.80 and 4 nickels are worth $0.20 and $2.80 plus $0.20 is $3.00. Answer checks.
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