document.write( "Question 175299: I have a story problem that consists of 2 parts. I can't even begin to figure out the first part so I definately cannot figure out the second. I was hoping there would be someone to help me out. Here is the problem:\r
\n" ); document.write( "\n" ); document.write( "The weight of an object follows this equation: w=Cr<-2> (the negative 2 is an exponent) where C is a constant, and the r is the distance that the object is from the center of the earth. \r
\n" ); document.write( "\n" ); document.write( "1. Solve the equation w=Cr<-2> for r.
\n" ); document.write( "2. Suppose that an object is 100 pounds when it is at sea level. Find the value of C that makes the equation true. (Sea level is 3,963 miles from the center of the earth)\r
\n" ); document.write( "\n" ); document.write( "Please help.
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Algebra.Com's Answer #130677 by ptaylor(2198)\"\" \"About 
You can put this solution on YOUR website!
(1)
\n" ); document.write( "\"w=Cr%5E%28-2%29\" or
\n" ); document.write( "\"w=C%2Fr%5E2\" multiply each side by \"r%5E2\"
\n" ); document.write( "\"wr%5E2=C\" divide each side by w
\n" ); document.write( "\"r%5E2=C%2Fw\" take the square root of each side
\n" ); document.write( "\"r=sqrt%28C%2Fw%29\"\r
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\n" ); document.write( "\n" ); document.write( "(2)
\n" ); document.write( "\"3963=sqrt%28C%2F100%29\" or
\n" ); document.write( "\"3963=%28sqrt%28C%29%29%2F10\" multiply each side by 10
\n" ); document.write( "\"39630=sqrt%28C%29\" take square root of each side
\n" ); document.write( "\"C=199.07\"\r
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\n" ); document.write( "\n" ); document.write( "Does this help??----ptaylor
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