document.write( "Question 175570: Rey can do a story in 3 hours while Joe can do it in 5 hours.In how many hours can the two boys do the work , if they worked together? \n" ); document.write( "
Algebra.Com's Answer #130655 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
Rey can do a story in 3 hours while Joe can do it in 5 hours.In how many hours can the two boys do the work , if they worked together?
\n" ); document.write( ":
\n" ); document.write( "Let t = time required if they work together
\n" ); document.write( ":
\n" ); document.write( "Let the completed job = 1 (1 story)
\n" ); document.write( ":
\n" ); document.write( "\"t%2F3\" + \"t%2F5\" = 1
\n" ); document.write( ":
\n" ); document.write( "Multiply equation by a multiple of the two denominators, 15 will do this:
\n" ); document.write( "15*\"t%2F3\" + 15*\"t%2F5\" = 15(1)
\n" ); document.write( "5t + 3t = 15
\n" ); document.write( ":
\n" ); document.write( "8t = 15
\n" ); document.write( "t = \"15%2F8\"
\n" ); document.write( "t = 1.875 hrs or 1 hr 52.5 minutes
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check solution, replace t with 1.875 in original equation:
\n" ); document.write( "\"1.875%2F3\" + \"1.875%2F5\" = 1
\n" ); document.write( ".625 + .375 = 1.00\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );