document.write( "Question 24513: Please help me with this problem:\r
\n" ); document.write( "\n" ); document.write( "3\"sqrt%284%29\" divided by 3\"sqrt%2832%29\"
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Algebra.Com's Answer #13062 by longjonsilver(2297)\"\" \"About 
You can put this solution on YOUR website!
both 4 and 32 scream out \"powers of 2\" to me...\r
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\n" ); document.write( "\n" ); document.write( "I am assuming the 3's are coefficients rather than a cube root.\r
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\n" ); document.write( "\n" ); document.write( "\"%283sqrt%284%29%29%2F%283sqrt%2832%29%29+\"
\n" ); document.write( "\"%28sqrt%282%5E2%29%29%2F%28sqrt%282%5E5%29%29+\"
\n" ); document.write( "\"sqrt%28%282%5E2%29%2F%282%5E5%29%29+\"
\n" ); document.write( "\"sqrt%281%2F%282%5E3%29%29+\"
\n" ); document.write( "or
\n" ); document.write( "\"sqrt%281%2F8%29\"
\n" ); document.write( "\"1%2Fsqrt%288%29\"\r
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\n" ); document.write( "\n" ); document.write( "which is \"%281%2Fsqrt%284%2A2%29%29\"
\n" ); document.write( "\"1%2F%28sqrt%284%29sqrt%282%29%29\"
\n" ); document.write( "\"1%2F%282sqrt%282%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "if the 3's are cube roots then we get the following:
\n" ); document.write( "\"3%28sqrt%282%5E2%29%29%2F%283sqrt%282%5E5%29%29+\"
\n" ); document.write( "\"3sqrt%28%282%5E2%29%2F%282%5E5%29%29+\"
\n" ); document.write( "\"%28%282%5E2%29%2F%282%5E5%29%29%5E%281%2F3%29+\"
\n" ); document.write( "\"%281%2F%282%5E3%29%29%5E%281%2F3%29+\"\r
\n" ); document.write( "\n" ); document.write( "\"1%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "jon.
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