document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=175542>Question 175542</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need to solve for x\r<BR>\n" );
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document.write( "25=5*10^(x/2)\r<BR>\n" );
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document.write( "I know I am supposed to use log to bring the x/2 down somehow but I just can't figure it out </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #130612 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=130612\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  I need to solve for x <BR>\n" );
document.write( "25=5*10^(x/2) <BR>\n" );
document.write( "Divide by 5<BR>\n" );
document.write( "5 = 10^(x/2)<BR>\n" );
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document.write( "No problem so far, right?<BR>\n" );
document.write( "Now take the log of both sides. Logs (base 10) are the exponents to which 10 is raised to get the number. Since the right side is already 10 to an exponent, the exponent is the log.<BR>\n" );
document.write( "That is, the log of 10^anything is...anything. In this case, it's x/2.<BR>\n" );
document.write( "-------------<BR>\n" );
document.write( "log(5) = x/2<BR>\n" );
document.write( "x = 2*log(5)<BR>\n" );
document.write( "x = log(25)<BR>\n" );
document.write( "x =~ 1.39794 </SPAN>\n" );
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