document.write( "Question 175333: make a quadratic equation with the maximum value 10 and the x intercepts 1 and 3 \n" ); document.write( "
Algebra.Com's Answer #130606 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! make a quadratic equation with the maximum value 10 and the x intercepts 1 and 3 \n" ); document.write( ": \n" ); document.write( "we know that the max value of y is on the axis of symmetry which is half-way \n" ); document.write( "between the intercepts so max (vertex) is a x=2; y=10 \n" ); document.write( "; \n" ); document.write( "we have three coordinates of this equation: \n" ); document.write( "x=1, y=0 \n" ); document.write( "x=2, y=10 \n" ); document.write( "x=3, y=0 \n" ); document.write( ": \n" ); document.write( "Using the form ax^2 + bx + c = y, we can solve for a, b, c \n" ); document.write( "; \n" ); document.write( "x=1,y=0 \n" ); document.write( "eq1: a + b + c = 0 \n" ); document.write( ": \n" ); document.write( "x=2,y=10 \n" ); document.write( "eq2: 4a + 2b + c = 10 \n" ); document.write( ": \n" ); document.write( "x=3,y=0 \n" ); document.write( "eq3: 9a + 3b + c = 0 \n" ); document.write( ": \n" ); document.write( "Using equations 2 and 1, eliminate c \n" ); document.write( "4a + 2b + c = 10 \n" ); document.write( " a + b + c = 0 \n" ); document.write( "-------------------subtraction eliminates c \n" ); document.write( "3a + b = 10 \n" ); document.write( ": \n" ); document.write( "Using equations 2 and 3, eliminate c again \n" ); document.write( "4a + 2b + c = 10 \n" ); document.write( "9a + 3b = c = 0 \n" ); document.write( "---------------------subtract \n" ); document.write( "-5a - b = 10 \n" ); document.write( ": \n" ); document.write( "Add these two a&b equations \n" ); document.write( "3a + b = 10 \n" ); document.write( "-5a- b = 10 \n" ); document.write( "----------------additions eliminates b \n" ); document.write( "-2a = 20 \n" ); document.write( "a = \n" ); document.write( "a = -10 \n" ); document.write( ": \n" ); document.write( "Find b using equation 3a + b = 10, substitute -10 for a \n" ); document.write( "3(-10) + b = 10 \n" ); document.write( "-30 + b = 10 \n" ); document.write( "b = 40 \n" ); document.write( ": \n" ); document.write( "Find c using eq1: \n" ); document.write( "-10 + 40 + c = 0 \n" ); document.write( "30 + c = 0 \n" ); document.write( "c = -30 \n" ); document.write( ": \n" ); document.write( "Our equation: y = -10x^2 + 40x - 30 \n" ); document.write( "; \n" ); document.write( "Looks like this: \n" ); document.write( " |