document.write( "Question 175513This question is from textbook
\n" ); document.write( ": Mary is three years older than her twin brothers. next year the sum of the ages of the three will be exactly 102 . how old are they now? \n" ); document.write( "
Algebra.Com's Answer #130592 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
Let the brothers be \"x\" years old. Then Mary is \"x+%2B+3\" years old. Next year the brothers will each be \"x+%2B+1\" and Mary will be \"x+%2B+4\". We are given that \"%28x+%2B+4%29+%2B+%28x+%2B+1%29+%2B+%28x+%2B+1%29+=+102\".\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Remove parentheses and collect terms:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"3x+%2B+6+=+102\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"3x+=+102+-+6+=+96\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+=+96%2F3+=+32\".\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So the brothers are 32 now and Mary is 35 now.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Check: 33 + 33 + 36 = 102.
\n" ); document.write( "
\n" );