document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=24539>Question 24539</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello - this question I am stuck on. \r<BR>\n" );
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document.write( "Solve x, y, z.\r<BR>\n" );
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document.write( "xy - 2(y^-2) + 3zy = 8<BR>\n" );
document.write( "2xy - 3(y^-2) + 2zy = 7<BR>\n" );
document.write( "-xy + (y^-2) + 2zy = 4\r<BR>\n" );
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document.write( "I first made a matrix:\r<BR>\n" );
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document.write( "1     -2     3    8<BR>\n" );
document.write( "2     -3     2    7<BR>\n" );
document.write( "-1     1     2     4\r<BR>\n" );
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document.write( "Then reduced and got\r<BR>\n" );
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document.write( "1     0     0     5/11<BR>\n" );
document.write( "0     1     0     -7/11<BR>\n" );
document.write( "0     0     1     23/11\r<BR>\n" );
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document.write( "This would make:\r<BR>\n" );
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document.write( "xy = 5/11<BR>\n" );
document.write( "(y^-2) = -7/11<BR>\n" );
document.write( "zy = 23/11\r<BR>\n" );
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document.write( "then solve by algebra and substitution.\r<BR>\n" );
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document.write( "This this correct?\r<BR>\n" );
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document.write( "Thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #13059 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=13059\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> EXCELLENT..YOU HAVE CORRECTLY IDENTIFIED THE PROBLEM AND METHOD OF SOLUTION..IT TAKES A GOOD EYE TO DETECT THIS AS 3 VARIABLE SIMULTANEOUS EQUATION IN XY,1/Y^2,YZ.YOUR MATRIX REDUCTION IS ALSO OK ,BUT I THINK YOU MADE SOME ARITHMAICAL ERROR IN DOING SO.THE FINAL REDUCED MATRIX IS ACTUALLY AS GIVEN BELOW.SEE MY COMMENTS.....\r<BR>\n" );
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document.write( "Solve x, y, z. <BR>\n" );
document.write( "xy - 2(y^-2) + 3zy = 8<BR>\n" );
document.write( "2xy - 3(y^-2) + 2zy = 7<BR>\n" );
document.write( "-xy + (y^-2) + 2zy = 4 <BR>\n" );
document.write( "I first made a matrix: ..VERY GOOD<BR>\n" );
document.write( "1 -2 3 8<BR>\n" );
document.write( "2 -3 2 7<BR>\n" );
document.write( "-1 1 2 4 <BR>\n" );
document.write( "Then reduced and got <BR>\n" );
document.write( "1 0 0 5/11<BR>\n" );
document.write( "0 1 0 -7/11<BR>\n" );
document.write( "0 0 1 23/11 <BR>\n" );
document.write( "THIS SHOULD BE <BR>\n" );
document.write( "1 0 0 5<BR>\n" );
document.write( "0 1 0 3<BR>\n" );
document.write( "0 0 1 3 <BR>\n" );
document.write( "YOU CAN SUBSTITUTE AND CHECK BACK.\r<BR>\n" );
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document.write( "This would make: <BR>\n" );
document.write( "xy = 5.............I<BR>\n" );
document.write( "(y^-2) = 3.........II<BR>\n" );
document.write( "zy = 3 .............III<BR>\n" );
document.write( "then solve by algebra and substitution. ...YA...CORRECT..FOR ALL THE GOOD WORK DONE BY YOU .LET ME COMPLETE THE SOLUTION<BR>\n" );
document.write( "I*III....XY^2Z=15.......IV<BR>\n" );
document.write( "II*IV.....XZ=45.........V<BR>\n" );
document.write( "I*III*V......(X^2)(Y^2)(Z^2)=5*3*45...OR....XYZ=15 SQRT 3......VI<BR>\n" );
document.write( "DIVIDING VI WITH I,III,V...WE GET <BR>\n" );
document.write( "X=5SQRT 3<BR>\n" );
document.write( "Y=1/SQRT 3<BR>\n" );
document.write( "Z=3SQRT 3\r<BR>\n" );
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document.write( "This this correct? <BR>\n" );
document.write( "Thanks<BR>\n" );
document.write( " </SPAN>\n" );
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