document.write( "Question 175519: x2 to the 2 nd power + sq root of 64=
\n" ); document.write( "for x=6
\n" ); document.write( "That's all i know it's for my grandaughter
\n" ); document.write( "

Algebra.Com's Answer #130585 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
I think you mean evaluate \"f%286%29\" for \"f%28x%29=x%5E2%2Bsqrt%2864%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Step 1: We know that \"8+%2A+8+=+64\", so we can say \"sqrt%2864%29+=+8\". Substituting:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x%5E2%2Bsqrt%2864%29=x%5E2%2B8\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Now substitute \"6\" for \"x\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"f%286%29+=+6%5E2+%2B+8+=+36+%2B+8+=+44\"
\n" ); document.write( "
\n" );