document.write( "Question 175480: i need help doing this problem:\r
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document.write( "-3a + b = 4 \r
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document.write( "-9a + 5b = -1\r
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document.write( "need this answered tonight!!! thank you!! \r
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document.write( "(this is a really neat place!!) \n" );
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Algebra.Com's Answer #130558 by Mathtut(3670)![]() ![]() ![]() You can put this solution on YOUR website! this is a system of equation that we will solve similtaneously \n" ); document.write( ": \n" ); document.write( "-3a + b = 4 ....eq 1 \n" ); document.write( "-9a + 5b = -1...eq 2 \n" ); document.write( ": \n" ); document.write( "multiply eq 1 by -3 \n" ); document.write( ": \n" ); document.write( "9a-3b=-12....revised eq 1 \n" ); document.write( "-9a+5b=-1....eq 2 \n" ); document.write( ": \n" ); document.write( "I lined the 2 equations up so you can see that when we add the equations together the a terms are eliminated because 9a-9a=0. We are left with \n" ); document.write( "-3b+5b=-12-1. \n" ); document.write( ": \n" ); document.write( "2b=-13 \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "now take b's found value and plug it back into either equation. I will use eq 1 \n" ); document.write( ": \n" ); document.write( "-3a + (-13/2)=4 ........now multiply all terms by 2 to get rid of fraction \n" ); document.write( ": \n" ); document.write( "-6a-13=8 \n" ); document.write( ": \n" ); document.write( "-6a=21 \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |