document.write( "Question 175467: Define A@B to be A/B + (A x B). What is the value of 20@(4@2)? \n" ); document.write( "
Algebra.Com's Answer #130552 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! First, find 4@2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "A@B = A/B + (A x B) ... Start with the given definition\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "4@2 = 4/2 + (4 x 2) ... Plug in A=4 and B=2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "4@2 = 4/2 + (8) ... Multiply\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "4@2 = 2 + (8) ... Divide\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "4@2 = 10 ... Add\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So 20@(4@2) simplifies to 20@10\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now find 20@10\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "A@B = A/B + (A x B) ... Start with the given definition\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "20@10 = 20/10 + (20 x 10) ... Plug in A=4 and B=2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "20@10 = 20/10 + (200) ... Multiply\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "20@10 = 2 + (200) ... Divide\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "20@10 = 202 ... Add\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So 20@(4@2)=202 \n" ); document.write( " |