document.write( "Question 24532: PLEASE HELP WITH THIS TOO!
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document.write( "In a certain triangle, the first angle measures 9 degrees less than the second angle. The third angle measures 3 degrees more than the second angle. Find the measures of all three angles.\r
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document.write( "I can solve this if I have the degrees of two sides, but this doesn't give any. I thought I should let x=second angle, x-9=first angle, and x+3=third angle but I didn't know where to go from there(or if that was the way to start)
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document.write( "THIS IS DUE BY 01/17/06. THANKS FOR YOUR TIME! \n" );
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Algebra.Com's Answer #13053 by Earlsdon(6294)![]() ![]() ![]() You can put this solution on YOUR website! Let the first angle be A, the second angle be B and the third angle be C. \n" ); document.write( "From the problem description, you can write: \n" ); document.write( "A = B-9 \n" ); document.write( "C = B+3\r \n" ); document.write( "\n" ); document.write( "And you already know (or should know) that for any plane triangle: A+B+C = 180 degrees.\r \n" ); document.write( "\n" ); document.write( "So, in A+B+C = 180, substitute for A and C the first two equations:\r \n" ); document.write( "\n" ); document.write( "(B-9) + B + (B+3) = 180 Simplify and solve for B. \n" ); document.write( "3B - 6 = 180 Add 6 to both sides of the equation. \n" ); document.write( "3B = 186 Divide both sides by 3. \n" ); document.write( "B = 62 \n" ); document.write( "A = B-9 \n" ); document.write( "A = 62-9 = 53 \n" ); document.write( "C = B+3 \n" ); document.write( "C = 62+3 = 65.\r \n" ); document.write( "\n" ); document.write( "The three angles are: \n" ); document.write( "A = 53 degrees. \n" ); document.write( "B = 62 degrees. \n" ); document.write( "C = 65 degrees.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |