document.write( "Question 175451: A passenger train travels 392 mi in the same time that it takes a freight train to
\n" ); document.write( "travel 322 mi. If the passenger train travels 20 mi/h faster than the freight train,
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Algebra.Com's Answer #130523 by ankor@dixie-net.com(22740)\"\" \"About 
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A passenger train travels 392 mi in the same time that it takes a freight
\n" ); document.write( " train to travel 322 mi. If the passenger train travels 20 mi/h faster than
\n" ); document.write( " the freight train, find the speed of each train.
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\n" ); document.write( "Let s = speed of the freight
\n" ); document.write( "then
\n" ); document.write( "(s+20) = speed of the passenger train
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\n" ); document.write( "Since the problems states the times are equal, write a time equation
\n" ); document.write( "Time = dist/speed
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\n" ); document.write( "Pass time = freight time
\n" ); document.write( " \"392%2F%28%28s%2B20%29%29\" = \"322%2Fs\"
\n" ); document.write( "Cross multiply
\n" ); document.write( "392s = 322(s+20)
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\n" ); document.write( "392s = 322s + 6440
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\n" ); document.write( "392s - 322s = 6440
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\n" ); document.write( "70s = 6440
\n" ); document.write( "s = \"6440%2F70\"
\n" ); document.write( "s = 92 mph is the freight
\n" ); document.write( "then
\n" ); document.write( "92 + 20 = 112 mph is the passenger train
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\n" ); document.write( "Check solution by finding the times of each
\n" ); document.write( "392/112 = 3.5 hrs
\n" ); document.write( "322/92 = 3.5 hrs
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