document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=24528>Question 24528</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I set up a table for this question, but the numbers I got were too big to be right. \r<BR>\n" );
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document.write( "Here is the problem:\r<BR>\n" );
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document.write( "A candy mix is being prepared by mixing candy that is worth $12 per pound with candy that is worth $15 per pound. The candy store wants to have 120 pounds of this mixture which will sell for $13.75 per pound. How many pounds of each type of candy should be used?\r<BR>\n" );
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document.write( "Find the number of pounds @$12 and @$15.\r<BR>\n" );
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document.write( "I made a table with x and y representing the # of lbs. With 120lbs. as the total. 12 and 15 as the price per pound and 13.75 for the total price per pound.<BR>\n" );
document.write( "In the third boxes of my table I wrote 12x, 15x, and 120(13.75)=1650.\r<BR>\n" );
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document.write( "Then I wrote the equation:  12x+15y=1650<BR>\n" );
document.write( "(here is where I get lost)<BR>\n" );
document.write( "I then did:  12(120-y)+y=1650<BR>\n" );
document.write( "=  1440-12y+y=1650                                                              =  1440-11y=1650<BR>\n" );
document.write( "  I subtracted 1440 from both sides to isolate the variable and came up with:      <BR>\n" );
document.write( "-11y=210<BR>\n" );
document.write( "then I divided -11y and 210 by -11= y= -19.09<BR>\n" );
document.write( "and then I solved for x by: 120-19.09= 100.91  x=100.91!!!!\r<BR>\n" );
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document.write( "I KNOW THIS IS TOTALLY WRONG, BUT THERE IS NOT ANYTHING IN MY TEXT BOOK TO SHOW ME HOW TO SOLVE THIS PROBLEM!!!! PLEASE HELP!! THIS HOMEWORK IS DUE BY 01/17/06<BR>\n" );
document.write( "HELP WILL BE GREATLY APPRECIATED! :) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #13052 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=13052\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Try this:<BR>\n" );
document.write( "Let x = the required number of pounds at $12.00 a pound (12x), then (120-x) = the number of pounds at $15.00 a pound 15(120-x). The sum of these are to equal 120 pounds at $13.75 a pound (120(13.75). Let's set up the equation to find x.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=12x+%2B+15%28120-x%29+=+120%2813.75%29 ALIGN=MIDDLE  ALT=\"12x+%2B+15%28120-x%29+=+120%2813.75%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > Simplify and solve for x.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=12x+-+15x+%2B+1800+=+1650 ALIGN=MIDDLE  ALT=\"12x+-+15x+%2B+1800+=+1650\"   DISABLED_style= \"max-width:90%; height:auto;\" > Combine like-terms.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-3x+%2B+1800+=+1650 ALIGN=MIDDLE  ALT=\"-3x+%2B+1800+=+1650\"   DISABLED_style= \"max-width:90%; height:auto;\" > Add 3x to both sides of the equation.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1800+=+1650+%2B+3x ALIGN=MIDDLE  ALT=\"1800+=+1650+%2B+3x\"   DISABLED_style= \"max-width:90%; height:auto;\" > Subtract 1650 from both sides.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=150+=+3x ALIGN=MIDDLE  ALT=\"150+=+3x\"   DISABLED_style= \"max-width:90%; height:auto;\" > Now divide both sides by 3.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+50 ALIGN=MIDDLE  ALT=\"x+=+50\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "The candy store will have to mix 50 pounds of $12.00 candy with 120-50= 70 pounds of $15.00 candy to obtain 120 pounds of $13.75 candy. </SPAN>\n" );
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