document.write( "Question 175440: times to unload a certain truck:\r
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document.write( "al,bob,chuck together t hours
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document.write( "al alone t+1
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document.write( "bob alone t+6
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document.write( "chuck alone 2t\r
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document.write( "find t \n" );
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Algebra.Com's Answer #130516 by ptaylor(2198) You can put this solution on YOUR website! \n" ); document.write( "al, bob, chuck together work at the rate of 1/t truck per hour \n" ); document.write( "al works at the rate of 1/(t+1) truck per hour \n" ); document.write( "bob works at the rate of 1/(t+6) truck per hour \n" ); document.write( "chuck works at the rate of 1/(2t) truck per hour\r \n" ); document.write( "\n" ); document.write( "Now we know that: \n" ); document.write( "(1/(t+1))+(1/(t+6))+(1/(2t))=1/t multiply each term by 2t(t+1)(t+6) \n" ); document.write( "2t(t+6)+2t(t+1)+(t+1)(t+6)=2(t+1)(t+6) get rid of parens \n" ); document.write( "2t^2+12t+2t^2+2t+t^2+7t+6=2t^2+14t+12 simplify \n" ); document.write( "5t^2+21t+6=2t^2+14t+12 subtract 2t^2, 14t and 12 from each side\r \n" ); document.write( "\n" ); document.write( "3t^2+7t-6=0 quadratic in standard form and it can be factored \n" ); document.write( "(3t-2)(t+3)=0 \n" ); document.write( "3t-2=0 \n" ); document.write( "t=2/3 hr---------------------------answer \n" ); document.write( "and \n" ); document.write( "t+3=0 \n" ); document.write( "t=-3 hrs----disregard--time in this case is positive\r \n" ); document.write( "\n" ); document.write( "CK \n" ); document.write( "1/(2/3 +1) + 1/(2/3+6) + 1/(2*2/3)=1/(2/3) \n" ); document.write( "3/5 + 3/20 + 3/4=3/2 \n" ); document.write( "12/20 + 3/20 =15/20=3/2 \n" ); document.write( "30/20=3/2 \n" ); document.write( "2/2=3/2\r \n" ); document.write( "\n" ); document.write( "Does this help??? ------ptaylor\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |