document.write( "Question 24521: Please show me how to solve this problem by completing the square. \"3x%5E2-2x%2B5=0\" \n" ); document.write( "
Algebra.Com's Answer #13051 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Well, it looks like you were on the right track!
\n" ); document.write( "Solve by completing the square:
\n" ); document.write( "\"3x%5E2-2x%2B5+=+0\" First divide through by 3.
\n" ); document.write( "\"x%5E2-%282%2F3%29x%2B5%2F3+=+0\" Now subtract 5/3 from both sides of the equation.
\n" ); document.write( "\"x%5E2-%282%2F3%29x+=+-5%2F3\" Complete the square in the x-terms by adding the square of half the x-coefficient \"%281%2F3%29%5E2+=+1%2F9\" to both sides.
\n" ); document.write( "\"x%5E2-%282%2F3%29x%2B1%2F9+=+%281%2F9%29-5%2F3\" Factor the left side and simplify.
\n" ); document.write( "\"%28x-1%2F3%29%5E2+=+-14%2F9\" Take the square root of both sides.
\n" ); document.write( "\"x-1%2F3+=+%281%2F3%29sqrt%2814%29\" Add 3 to both sides.
\n" ); document.write( "\"x+=3%2B-sqrt%2814%29%2F3\"
\n" ); document.write( "
\n" );