document.write( "Question 175420: an airplane travwl 100km/h then another airplane. In 4 hours the faster airplanes travel the same distance as the slower airplane travel in 6 hours. Find the rate of the faster airplane. \n" ); document.write( "
Algebra.Com's Answer #130482 by rapaljer(4671)\"\" \"About 
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Let x = speed of the slower plane
\n" ); document.write( "x+100 = speed of the faster plane\r
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\n" ); document.write( "\n" ); document.write( "Distance = Rate * Time\r
\n" ); document.write( "\n" ); document.write( "4(x+100)=6x
\n" ); document.write( "4x+400=6x
\n" ); document.write( "400=2x
\n" ); document.write( "x= 200 mph slower plane
\n" ); document.write( "x+100 = 300 mph faster plane\r
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\n" ); document.write( "\n" ); document.write( "Check: Faster plane (300 mph) in 4 hours travels 1200 miles
\n" ); document.write( "Slower plane (200 mph) in 6 hours travels 1200 miles.\r
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\n" ); document.write( "\n" ); document.write( "R^2
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