document.write( "Question 175420: an airplane travwl 100km/h then another airplane. In 4 hours the faster airplanes travel the same distance as the slower airplane travel in 6 hours. Find the rate of the faster airplane. \n" ); document.write( "
Algebra.Com's Answer #130482 by rapaljer(4671) You can put this solution on YOUR website! Let x = speed of the slower plane \n" ); document.write( "x+100 = speed of the faster plane\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Distance = Rate * Time\r \n" ); document.write( "\n" ); document.write( "4(x+100)=6x \n" ); document.write( "4x+400=6x \n" ); document.write( "400=2x \n" ); document.write( "x= 200 mph slower plane \n" ); document.write( "x+100 = 300 mph faster plane\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Check: Faster plane (300 mph) in 4 hours travels 1200 miles \n" ); document.write( "Slower plane (200 mph) in 6 hours travels 1200 miles.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "R^2 \n" ); document.write( " |