document.write( "Question 175400: Find two consecutive integers such that four times the the larger exceeds three times the smaller by 23. \n" ); document.write( "
Algebra.Com's Answer #130479 by rapaljer(4671)![]() ![]() You can put this solution on YOUR website! Let x = first (smaller) \n" ); document.write( "x+ 1 = second (larger)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "4(x+1) - 3(x) = 23 \n" ); document.write( "4x +4 - 3x = 23 \n" ); document.write( "x+4=23 \n" ); document.write( "x= 19 \n" ); document.write( "x+1 = 20\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Check: 4(20)= 80 \n" ); document.write( "3(19) = 57\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Difference = 23\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "R^2 \n" ); document.write( " \n" ); document.write( " |