document.write( "Question 175400: Find two consecutive integers such that four times the the larger exceeds three times the smaller by 23. \n" ); document.write( "
Algebra.Com's Answer #130479 by rapaljer(4671)\"\" \"About 
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Let x = first (smaller)
\n" ); document.write( "x+ 1 = second (larger)\r
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\n" ); document.write( "\n" ); document.write( "4(x+1) - 3(x) = 23
\n" ); document.write( "4x +4 - 3x = 23
\n" ); document.write( "x+4=23
\n" ); document.write( "x= 19
\n" ); document.write( "x+1 = 20\r
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\n" ); document.write( "\n" ); document.write( "Check: 4(20)= 80
\n" ); document.write( "3(19) = 57\r
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\n" ); document.write( "\n" ); document.write( "Difference = 23\r
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\n" ); document.write( "\n" ); document.write( "R^2
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