document.write( "Question 175417: a father is now four times as old as his son. If the sum of their ages ten years ago was sixty. find thrie present ages \n" ); document.write( "
Algebra.Com's Answer #130471 by rapaljer(4671)![]() ![]() You can put this solution on YOUR website! Let x = son's age \n" ); document.write( "4x = father's age\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x-10 = son's age 10 years ago \n" ); document.write( "4x-10= father's age 10 years ago\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x-10 + 4x-10=60 \n" ); document.write( "5x-20=60 \n" ); document.write( "5x=80 \n" ); document.write( "x=16 son's age now \n" ); document.write( "4x=64 father's age now (or was that his grandfather??)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Check: 10 years ago, son was 6 and father was 54, and the sumof their ages is 60. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "R^2 \n" ); document.write( " \n" ); document.write( " |