document.write( "Question 175404: The length of a rectangle is five inches more than its width. The perimeter is 66 inches. Find the dimensions of the rectangle. \n" ); document.write( "

Algebra.Com's Answer #130464 by EMStelley(208) $\"\"$ $\"About$

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Let's call the width of the rectangle w. Then we can denote the length of the rectangle by w+5 since the length is 5 inches more than its width. Remembering that the perimeter equation is 2*length + 2*width, we get that\r
\n" ); document.write( "\n" ); document.write( " $\"2w+%2B+2%28w%2B5%29+=+66\"$
\n" ); document.write( "So
\n" ); document.write( " $\"2w+%2B+2w+%2B+10+=+66\"$
\n" ); document.write( "Combining like terms and subtracting 10 yields
\n" ); document.write( " $\"4w+=+56\"$
\n" ); document.write( "Dividing both sides by 4, we get
\n" ); document.write( " $\"w+=+14\"$
\n" ); document.write( "So the width of the rectangle is 14 inches. Using the knowledge we have about the length, that means the length is 19 inches. \n" ); document.write( "

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