document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=175395>Question 175395</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find three consecutive integers such that the sum of the first two integers is 24 more than the third integer.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #130459 by </B><A HREF=/tutors/aboutme.mpl?userid=EMStelley><B>EMStelley(208)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=EMStelley><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=EMStelley><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=130459\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call the first integer x.  Then we can denote the next two by x+1 and x+2 since they are consecutive.  Then the \"sum of the first two\" can be written as\r<BR>\n" );
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document.write( "x + (x+1)\r<BR>\n" );
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document.write( "And \"24 more than the third integer\" can be written as\r<BR>\n" );
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document.write( "(x+2) + 24\r<BR>\n" );
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document.write( "Thus we have the equation\r<BR>\n" );
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document.write( "x + (x+1) = (x+2) + 24<BR>\n" );
document.write( "So<BR>\n" );
document.write( "2x + 1 = x + 26<BR>\n" );
document.write( "Subtracting x from both sides and subtracting 1 from both sides we get\r<BR>\n" );
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document.write( "x = 25\r<BR>\n" );
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document.write( "This means that the three integers are 25, 26 and 27. </SPAN>\n" );
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