document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=175372>Question 175372</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0395977223/algebrahomeworkh>algebra sturcture and method</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> can you please help me solve: (((n^3-27/n-3))) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #130454 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=130454\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> can you please help me solve: (((n^3-27/n-3)))<BR>\n" );
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document.write( "This can't be solved, but it can be simplified.<BR>\n" );
document.write( "Notice that in the NUM, both terms are the third power, n^3 and 3^3.  Any binomial with odd exponents can be factored.<BR>\n" );
document.write( "You can always just divide it out, too, with long division of synthetic division.<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=n%5E3+-+27+=+%28n-3%29%2A%28n%5E2+%2B+3n+%2B+9%29 ALIGN=MIDDLE  ALT=\"n%5E3+-+27+=+%28n-3%29%2A%28n%5E2+%2B+3n+%2B+9%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "The (n-3)'s cancel, so<BR>\n" );
document.write( "it's <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=n%5E2+%2B+3n+%2B+9 ALIGN=MIDDLE  ALT=\"n%5E2+%2B+3n+%2B+9\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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