document.write( "Question 175375This question is from textbook college algebras
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\n" ); document.write( "\n" ); document.write( "f(x)= \"2x%5E2%2B3x-1\" I need to graph this quadratic funtion by completing the square. I figured out the vertix as -17/8,-3/4 I am stuck on figuring out the two other points. I need help, thank you
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Algebra.Com's Answer #130433 by EMStelley(208)\"\" \"About 
You can put this solution on YOUR website!
First, let's complete the square.\r
\n" ); document.write( "\n" ); document.write( "f(x) = \"2x%5E2+%2B+3x+-+1\" = \"2%28x%5E2+%2B+%283%2F2%29x%29+-+1\"
\n" ); document.write( "=\"2%28x%5E2+%2B+%283%2F2%29x+%2B+%283%2F4%29%5E2%29+-+1+-+2%283%2F4%29%5E2\"
\n" ); document.write( "=\"2%28x+%2B+%283%2F4%29%29%5E2+-+1+-+%289%2F8%29\"
\n" ); document.write( "=\"2%28x+%2B+%283%2F4%29%29%5E2+-+%2817%2F8%29\"\r
\n" ); document.write( "\n" ); document.write( "This tells us that the vertex of the parabola is (-3/4, -17/8), which is backwards from what you stated in the problem. When you say that you are stuck figuring out the other two points, I assume you are referencing the x and y intercepts. The y intercept is obtained by setting x to 0 in the original problem. So f(0) = -1 means the y intercept is (0, -1). In order to find the x intercepts, you set y = 0, and this is easier using the form above (found by completing the square).\r
\n" ); document.write( "\n" ); document.write( "So
\n" ); document.write( "0 = \"2%28x+%2B+%283%2F4%29%29%5E2+-+%2817%2F8%29\"
\n" ); document.write( "17/8 = \"2%28x+%2B+%283%2F4%29%29%5E2\"
\n" ); document.write( "17/16 = \"%28x+%2B+%283%2F4%29%29%5E2\"
\n" ); document.write( "\"%2B-sqrt%2817%2F16%29+=+x+%2B+%283%2F4%29\"
\n" ); document.write( "So \"x+=+-3%2F4+%2B-sqrt%2817%2F16%29\", which gives you your two x intercepts. Hope this helps!
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