document.write( "Question 175340: An apprentice unpacked 12 dozen fragile lighting fixtures. He was to receive $3 for each fixture that he unpacked safely and he agreed to pay $25 for every one that he broke. If the amount due him for his work was $236, how many did he break? \n" ); document.write( "
Algebra.Com's Answer #130406 by nycsub_teacher(90) ![]() You can put this solution on YOUR website! I got 2 equations here . \n" ); document.write( "Let x be the number of successful lightning fixtures \n" ); document.write( "Let y be the number of broken lightning fixtures. \r \n" ); document.write( "\n" ); document.write( "12 dozen = 12 x 12 or 144\r \n" ); document.write( "\n" ); document.write( "x + y = 144 \n" ); document.write( "3x - 25y = 236\r \n" ); document.write( "\n" ); document.write( "We have two equations in two unknowns.\r \n" ); document.write( "\n" ); document.write( "Can you take it from here?\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |