document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=175341>Question 175341</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 6-3/4÷3=? & 8÷1-1/3=? please help me I'm having the hardest time trying to figure out these type of problems and fractions are my weakness. i've read many fractions problems but i still dan't get it. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #130405 by </B><A HREF=/tutors/aboutme.mpl?userid=KnightOwlTutor><B>KnightOwlTutor(293)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=KnightOwlTutor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=KnightOwlTutor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=130405\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> first you solve for 6-3/4   You need to find the common denominator for both numbers in this case it is four. the number 6 becomes 24/4 you haven't changed the number it is still the same quantity but you can now perform the subtraction part with the fraction.64/4-3/4=21/4 divided by 3=7/4\r<BR>\n" );
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document.write( "8 divided by 1 is still eight  but we need to find a common denominator to solve the problem in this case it is 3. 24/3-1/3=23/3 </SPAN>\n" );
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