document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=175256>Question 175256</A>: <I><SPAN STYLE=\"word-break: break-all;\">        __                                  __<BR>\n" );
document.write( "Given: CK is the perpendicular bisector of AE\r<BR>\n" );
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document.write( "Prove: triangle CAK is congruent to triangle CEK </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #130352 by </B><A HREF=/tutors/aboutme.mpl?userid=gonzo><B>gonzo(654)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=gonzo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=130352\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> ck is the perpendicular bisector of ae (given).<BR>\n" );
document.write( "this means that ac = ce (bisector of a line splits the line into 2 congruent parts)<BR>\n" );
document.write( "this also means that angle ack equals angle eck = 90 degrees (perpendicular line creates 90 degree angle with the line it intersects)<BR>\n" );
document.write( "kc congruent to kc (same line)<BR>\n" );
document.write( "triangle akc congruent to triangle ekc (sas)<BR>\n" );
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document.write( "the words may not be exactly the way they would put them in your book but the concept is accurate.<BR>\n" );
document.write( "the triangles are congruent by sas.<BR>\n" );
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document.write( "   </SPAN>\n" );
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