document.write( "Question 175244This question is from textbook Algebra 1
\n" ); document.write( ": I am supposed to write the slope-intercept form of an equation that passes through the given point and is perpendicular to the graph of each equation.
\n" ); document.write( "(1,-3), y=1/2x+4 \n" ); document.write( "

Algebra.Com's Answer #130332 by solver91311(24713) $\"\"$ $\"About$

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First thing is to remember that perpendicular lines have slopes that are negative reciprocals. That is to say that if $\"L%5B1%5D\"$ has a slope $\"m%5B1%5D\"$ and $\"L%5B2%5D\"$ has a slope $\"m%5B2%5D\"$ then $\"L%5B1%5D\"$ is perpendicular to $\"L%5B2%5D\"$ if and only if $\"m%5B1%5D=%28-1%29%2Fm%5B2%5D\"$ .\r
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\n" ); document.write( "\n" ); document.write( "The slope of your given line is already in slope-intercept form, so you can see that the slope of the given line is $\"1%2F2\"$ because $\"1%2F2\"$ is the coefficient on the $\"x\"$ term. That means that the slope of any line perpendicular to the given line must be $\"%28-1%29%2F%281%2F2%29=-2\"$ .\r
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\n" ); document.write( "\n" ); document.write( "Knowing the slope and a point, you can use the point-slope form of a line to create the desired equation. The point slope form is: $\"y-y%5B1%5D=m%28x+-+x%5B1%5D%29\"$ where $\"m\"$ is the slope and ( $\"x%5B1%5D\"$ , $\"y%5B1%5D\"$ ) are the coordinates of the given point.\r
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\n" ); document.write( "\n" ); document.write( "Just plug in the numbers and then solve the resulting equation for $\"y\"$ to put the equation into slope-intercept form. \n" ); document.write( "

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