document.write( "Question 175215: How do I solve this problem? the first two terms of an arithmetic sequence are a(base1)=2 and a(base2)=4. what is the a(base10)? \n" ); document.write( "
Algebra.Com's Answer #130312 by gonzo(654)![]() ![]() ![]() You can put this solution on YOUR website! the formula for the nth term of a geometric sequence is: \n" ); document.write( "--- \n" ); document.write( " \n" ); document.write( "--- \n" ); document.write( "you are given \n" ); document.write( "you use them to find r as follows: \n" ); document.write( " \n" ); document.write( "substituting 4 for \n" ); document.write( "4 = 2*r^1 = 2*r \n" ); document.write( "solving for r, you get \n" ); document.write( "r = 2 \n" ); document.write( "--- \n" ); document.write( "you now have r, and you can substitute in the general equation as follows: \n" ); document.write( " \n" ); document.write( "substitute 2 for r, and 2 for \n" ); document.write( " \n" ); document.write( "--- \n" ); document.write( "the 10th term in the sequence is 1024. \n" ); document.write( "you can test this by doing it the hard way (each term is done separately) as follows: \n" ); document.write( "a(1) = 2 \n" ); document.write( "a(2) = 4 \n" ); document.write( "a(3) = 8 \n" ); document.write( "a(4) = 16 \n" ); document.write( "a(5) = 32 \n" ); document.write( "a(6) = 64 \n" ); document.write( "a(7) = 128 \n" ); document.write( "a(8) = 256 \n" ); document.write( "a(9) = 512 \n" ); document.write( "a(10) = 1024 \n" ); document.write( "--- \n" ); document.write( "each succeeding number is multiplied by the ratio. \n" ); document.write( "you do that 9 times which is the same as multiplying the original number by 2^9. \n" ); document.write( " \n" ); document.write( " |