document.write( "Question 175233: i cant figure out how to get \"X\" and \"Y\"...\r
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document.write( "4x + 6y = 38
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document.write( "10x + 8Y = 60\r
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document.write( "they have steps but i dont understand them, please help \n" );
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Algebra.Com's Answer #130310 by monika_p(71)![]() ![]() ![]() You can put this solution on YOUR website! one of the method to solve system of equation is method of elimination. \n" ); document.write( "4x+6y=38 \n" ); document.write( "10x+8y=60 \n" ); document.write( "lets eliminate x, to do so you have to multiply both equations first by 10 and second by -4 then you will get \n" ); document.write( "40x+60y=380 \n" ); document.write( "-40x-32y=-240 \n" ); document.write( "as you see you got 40x in first equation and -40x in second - opposits, after adding first equation to the second x will be eliminated: \n" ); document.write( "40x-40x+60y-32y=380-240 \n" ); document.write( "28y=140 / divide both sides by 28 \n" ); document.write( "y=5\r \n" ); document.write( "\n" ); document.write( "to find x substitute y=5 in either first or second equation\r \n" ); document.write( "\n" ); document.write( "4x+6*5=38 \n" ); document.write( "4x+30=38 \n" ); document.write( "4x=8 \n" ); document.write( "x=2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If you want eliminate y you will get same results: \n" ); document.write( "4x+6y=38/*8 \n" ); document.write( "10x+8y=60/*-6\r \n" ); document.write( "\n" ); document.write( "32x+48y=304 \n" ); document.write( "-60x-48y=-360 \n" ); document.write( "------------------ \n" ); document.write( "-28x=-56 / divide by -28 \n" ); document.write( "x=2\r \n" ); document.write( "\n" ); document.write( "then 10*2+8y=60 \n" ); document.write( "8y=60-20 \n" ); document.write( "8y=40 \n" ); document.write( "y=5 \n" ); document.write( " |