document.write( "Question 175216: The first two terms of a geometric sequence are a(base1)=1/3 and a(base2)=1/6. How do I find a(base8) the eighth term? \n" ); document.write( "
Algebra.Com's Answer #130308 by Edwin McCravy(20055)\"\" \"About 
You can put this solution on YOUR website!
The first two terms of a geometric sequence are \"a%5B1%5D=1%2F3\" and \"a%5B2%5D=1%2F6\". How do I find \"a%5B8%5D\", the eighth term?
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document.write( "First find the common ratio, \"r\", by dividing any term by\r\n" );
document.write( "its preceding term.  So \r\n" );
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document.write( "Now use the formula for the \"n\"th term:\r\n" );
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document.write( "\"matrix%281%2C4%2Ca%5Bn%5D%2C+%22=%22%2C+a%5B1%5D%2Cr%5E%28n-1%29%29\" \r\n" );
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document.write( "Substitute \"n=8\"\r\n" );
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document.write( "\"matrix%281%2C3%2Ca%5B8%5D%2C+%22=%22%2C+a%5B1%5Dr%5E%288-1%29%29\"\r\n" );
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document.write( "\"matrix%281%2C3%2Ca%5B8%5D%2C+%22=%22%2C+a%5B1%5Dr%5E7%29\"\r\n" );
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document.write( "\"matrix%281%2C3%2Ca%5B8%5D%2C+%22=%22%2C+%281%2F3%29%281%2F2%29%5E7%29\"\r\n" );
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document.write( "\"matrix%281%2C3%2Ca%5B8%5D%2C+%22=%22%2C+%281%2F3%29%28%281%5E7%29%2F%282%5E7%29%29%29\"\r\n" );
document.write( "            \r\n" );
document.write( "\"matrix%281%2C3%2Ca%5B8%5D%2C+%22=%22%2C+%281%2F3%29%281%2F128%29%29\"\r\n" );
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document.write( "\"matrix%281%2C3%2Ca%5B8%5D%2C+%22=%22%2C+1%2F384%29\"\r\n" );
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document.write( "Edwin
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