document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=175230>Question 175230</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please solve x + 1 = 2/3x algrbracially. Please, step by step, I need to see how the answer is -3. Cannot figure this out. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #130305 by </B><A HREF=/tutors/aboutme.mpl?userid=monika_p><B>monika_p(71)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=monika_p><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=130305\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> To solve this equation group all x on one side and rest on the other side of = sign. Remember that whatever you do to left side of the equation the same you have to do to the right, and opposit. \r<BR>\n" );
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document.write( "x+1=2/3x  subtract 2/3x from both sides so you will not have any x on the right side<BR>\n" );
document.write( "x-2/3x-1=2/3x-2/3x  <BR>\n" );
document.write( "x-2/3x-1=0    add 1 to both sides to remove number from rigt side (we want only x there)<BR>\n" );
document.write( "x-2/3x-1+1=-1<BR>\n" );
document.write( "x-2/3x=-1   <BR>\n" );
document.write( "3/3x-2/3x=-1<BR>\n" );
document.write( "1/3x=-1  /3 multiply by 3 to get just x on the left side<BR>\n" );
document.write( "x=-3  </SPAN>\n" );
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