document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=175231>Question 175231</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me expalin the answer to this problem -2(1+5a)=-4+6(a+3) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #130304 by </B><A HREF=/tutors/aboutme.mpl?userid=EMStelley><B>EMStelley(208)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=EMStelley><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=EMStelley><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=130304\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The first step is to distribute through on both sides.  So<BR>\n" );
document.write( "-2(1+5a) = -4+6(a+3) becomes\r<BR>\n" );
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document.write( "-2(1) + -2(5a) = -4 + 6a + 6(3)\r<BR>\n" );
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document.write( "-2 - 10a = -4 + 6a + 18\r<BR>\n" );
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document.write( "-2 - 10a = 14 + 6a\r<BR>\n" );
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document.write( "Next, we need to combine the \"a\" terms and combine the constants.  So, add 10a to both sides, and subtract 14 from both sides.\r<BR>\n" );
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document.write( "-16 = 16a\r<BR>\n" );
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document.write( "Lastly, dividing by 16 on both sides yields a = -1.<BR>\n" );
document.write( "Don't forget to always check your work! </SPAN>\n" );
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