document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=24467>Question 24467</A>: <I><SPAN STYLE=\"word-break: break-all;\"> in triangle EFG, FH is the bisector of angle F. if EH=6 and HG= 9, find the ratio of FG:EF. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #13028 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=13028\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> IN A TRIANGLE THE ANGLE BISECTOR OF ANY ANGLE DIVIDES THE OPPOSITE SIDE IN THE RATIO OF 2 ADJACENT SIDES OF THE TRIANGLE<BR>\n" );
document.write( "HERE EFG IS A TRIANGLE, FH is the bisector of angle F.IT MEETS THE OPPOSITE SIDE EG AT H.HENCE AS PER THE THEOREM WE HAVE <BR>\n" );
document.write( "EH/HG=FE/FG<BR>\n" );
document.write( "if EH=6 and HG= 9, <BR>\n" );
document.write( "HENCE EH/HG=6/9=FE/FG<BR>\n" );
document.write( "FG/FE=9/6=3/2<BR>\n" );
document.write( "the ratio of FG:EF=3:2\r<BR>\n" );
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