document.write( "Question 175202: Given that (x+3) and (x-1) are both factors of the same expression x^3+ax^2-bx-a,find the values of the constants a and b.
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document.write( "Determine the third factor or the expression. \n" );
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Algebra.Com's Answer #130276 by stanbon(75887) ![]() You can put this solution on YOUR website! Given that (x+3) and (x-1) are both factors of the same expression x^3+ax^2-bx-a,find the values of the constants a and b. \n" ); document.write( "Determine the third factor or the expression. \n" ); document.write( "-------------------------------------------------- \n" ); document.write( "If x-1 is a factor, f(1) = 0 \n" ); document.write( "f(1) = 1^3 + a(1^2) - b(1) -a = 1 + a -b -a = 1-b = 0 \n" ); document.write( "Therefore b = 1 \n" ); document.write( "------------------------- \n" ); document.write( "If x+3 is a factor, f(-3) = 0 \n" ); document.write( "f(-3) = (-3)^3 + a(-3)^2 - b(-3) -a = 0 \n" ); document.write( "-27 + 9a +3b -a = 0 \n" ); document.write( "Substitute b=1 and get \n" ); document.write( "-27 +8a + 3 = 0 \n" ); document.write( "8a = 24 \n" ); document.write( "a = 3 \n" ); document.write( "=========== \n" ); document.write( "f(x) = x^3+ax^2-bx-a \n" ); document.write( "f(x) = x^3 + 3x^2 -x - 3 \n" ); document.write( "----------------------- \n" ); document.write( "Use synthetic division to find the 3rd factor: \n" ); document.write( "1)....1....3....-1....-3 \n" ); document.write( ".......1......4...3...|..0 \n" ); document.write( "-3).....1......1..|..0\r \n" ); document.write( "\n" ); document.write( "3rd factor: x + 1 \n" ); document.write( "========================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |