document.write( "Question 175202: Given that (x+3) and (x-1) are both factors of the same expression x^3+ax^2-bx-a,find the values of the constants a and b.
\n" ); document.write( "Determine the third factor or the expression.
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Algebra.Com's Answer #130276 by stanbon(75887)\"\" \"About 
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Given that (x+3) and (x-1) are both factors of the same expression x^3+ax^2-bx-a,find the values of the constants a and b.
\n" ); document.write( "Determine the third factor or the expression.
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\n" ); document.write( "If x-1 is a factor, f(1) = 0
\n" ); document.write( "f(1) = 1^3 + a(1^2) - b(1) -a = 1 + a -b -a = 1-b = 0
\n" ); document.write( "Therefore b = 1
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\n" ); document.write( "If x+3 is a factor, f(-3) = 0
\n" ); document.write( "f(-3) = (-3)^3 + a(-3)^2 - b(-3) -a = 0
\n" ); document.write( "-27 + 9a +3b -a = 0
\n" ); document.write( "Substitute b=1 and get
\n" ); document.write( "-27 +8a + 3 = 0
\n" ); document.write( "8a = 24
\n" ); document.write( "a = 3
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\n" ); document.write( "f(x) = x^3+ax^2-bx-a
\n" ); document.write( "f(x) = x^3 + 3x^2 -x - 3
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\n" ); document.write( "Use synthetic division to find the 3rd factor:
\n" ); document.write( "1)....1....3....-1....-3
\n" ); document.write( ".......1......4...3...|..0
\n" ); document.write( "-3).....1......1..|..0\r
\n" ); document.write( "\n" ); document.write( "3rd factor: x + 1
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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