document.write( "Question 175196: a rectangle is three times as long as it is wide . if its length and width are both decresed by 2cm its area is decreased by 36 cm squared . find its original dimensions \n" ); document.write( "
Algebra.Com's Answer #130268 by KnightOwlTutor(293)![]() ![]() You can put this solution on YOUR website! We know that the difference between the 2 areas is 36. Therefore we are going to set up the equation of subtracting the two areas to get the original dimensions.\r \n" ); document.write( "\n" ); document.write( "x=width of the original rectangle \n" ); document.write( "3x=the length of the original rectangle\r \n" ); document.write( "\n" ); document.write( "x-2=width of the smaller rectangle \n" ); document.write( "3x-2=length of the smaller rectangle\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the area of a rectangle is width X length\r \n" ); document.write( "\n" ); document.write( "Area of the original rectangle-Area of smaller rectangle=36\r \n" ); document.write( "\n" ); document.write( "(3x*x)-[(x-2)(3x-2)]=36\r \n" ); document.write( "\n" ); document.write( "Use the foil method \r \n" ); document.write( "\n" ); document.write( "3x^2-2x-6x+4\r \n" ); document.write( "\n" ); document.write( "(3x*x)-[3x^2-2x-6x+4]=36\r \n" ); document.write( "\n" ); document.write( "multply -1 to each term contained within the bracket. \n" ); document.write( "Make sure to pay attention to the sign. \n" ); document.write( "(+)(-)=(-) \n" ); document.write( "(-)(-)=(+)\r \n" ); document.write( "\n" ); document.write( "(3x^2-3x^2+2x+6x-4=36\r \n" ); document.write( "\n" ); document.write( "Combine like terms and simplify\r \n" ); document.write( "\n" ); document.write( "(2+6)x-4=36\r \n" ); document.write( "\n" ); document.write( "8x-4=36\r \n" ); document.write( "\n" ); document.write( "Add 4 to both sides of the equation\r \n" ); document.write( "\n" ); document.write( "8x=40\r \n" ); document.write( "\n" ); document.write( "divide both sides by 8\r \n" ); document.write( "\n" ); document.write( "x=5\r \n" ); document.write( "\n" ); document.write( "The dimensions of the original rectangle was 5,15\r \n" ); document.write( "\n" ); document.write( "Let us double check our answer\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the dimensions of the smaller rectangle is 3,13\r \n" ); document.write( "\n" ); document.write( "(3*15)-(3*13)=36 75-39=36\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |