document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=175197>Question 175197</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a rectangle is twice as long as it is wide . if both its dimensions are increased 4 m , its area  is increaed by 88 m squared make a sketch and find its original dimensions  of the original rectangle </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #130266 by </B><A HREF=/tutors/aboutme.mpl?userid=actuary><B>actuary(112)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=actuary><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=130266\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let l = the original length of the original rectangle\r<BR>\n" );
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document.write( "Let w = the original width of the original rectangle\r<BR>\n" );
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document.write( "From the description of the problem, we can construct the following two equations\r<BR>\n" );
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document.write( "l=2*w  (Equation #1)\r<BR>\n" );
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document.write( "(l+4)*(w+4)=l*w+88 (Equation #2)\r<BR>\n" );
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document.write( "Substitute equation #1 into equation #2\r<BR>\n" );
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document.write( "(2w+4)*(w+4)=(2w*w)+88\r<BR>\n" );
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document.write( "2w^2+4w+8w+16=2w^2+88\r<BR>\n" );
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document.write( "collect like terms on the same side of the equation\r<BR>\n" );
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document.write( "2w^2+2w^2 +12w+16-88=0\r<BR>\n" );
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document.write( "4w^2+12w-72=0\r<BR>\n" );
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document.write( "Since 4 is afactor of each term, divide both sides of the equation by 4\r<BR>\n" );
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document.write( "w^2+3w-18=0\r<BR>\n" );
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document.write( "The quadratic equation can be factored into (w+6)*(w-3)=0 \r<BR>\n" );
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document.write( "Therefore w=-6 or w=3\r<BR>\n" );
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document.write( "w=-6 can be rejected because the length of a rectangle can't be negative so<BR>\n" );
document.write( "w=3 and from equation #1 l=2*w=2*3=6\r<BR>\n" );
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document.write( "I hope that this helps.  The difficult part of the problem probably was to construct equation #1 and to factor the equation after performing all of the arithmetic operations. \r<BR>\n" );
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document.write( " </SPAN>\n" );
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