document.write( "Question 175158: The length of a rectangle is five inches more than its width. The perimeter is 66 inches. Find the dimensions of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #130237 by actuary(112)![]() ![]() ![]() You can put this solution on YOUR website! Let x equal the width of the rectangle. \n" ); document.write( "Let y equal the length of the rectangle.\r \n" ); document.write( "\n" ); document.write( "The description of the problem leads to the equations\r \n" ); document.write( "\n" ); document.write( "l=w+5 Equation #1)\r \n" ); document.write( "\n" ); document.write( "2*l+2*w=66 in. Equation #2)\r \n" ); document.write( "\n" ); document.write( "Substitute equation #1 into equation #2\r \n" ); document.write( "\n" ); document.write( "2*(w+5)+2*w=66 in.\r \n" ); document.write( "\n" ); document.write( "Solve the equation for w\r \n" ); document.write( "\n" ); document.write( "2w+10+2w=66 in.\r \n" ); document.write( "\n" ); document.write( "Collect like terms\r \n" ); document.write( "\n" ); document.write( "2w+2w=66-10 \n" ); document.write( "4w+56\r \n" ); document.write( "\n" ); document.write( "Solve for w\r \n" ); document.write( "\n" ); document.write( "w=56/4 = 14\r \n" ); document.write( "\n" ); document.write( "So, from equation #1) l=w+5=14+5=19\r \n" ); document.write( "\n" ); document.write( "I hope that this helps. \n" ); document.write( " |