document.write( "Question 175156: Find two consecutive integers such that four times the larger exceeds three times the smaller by 23.
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Algebra.Com's Answer #130231 by actuary(112)![]() ![]() ![]() You can put this solution on YOUR website! Let x be the first integer. \n" ); document.write( "So the second integer is x+1 \n" ); document.write( "The description of the problems leads to the inequality\r \n" ); document.write( "\n" ); document.write( "4*(x+1)>3*x+23 Since x+1 is greater than x\r \n" ); document.write( "\n" ); document.write( "Simplifyling, we have\r \n" ); document.write( "\n" ); document.write( "4x+4>3x+23\r \n" ); document.write( "\n" ); document.write( "4x-3x>23-4\r \n" ); document.write( "\n" ); document.write( "x>19\r \n" ); document.write( "\n" ); document.write( "So x = 20 and x = 21 works \n" ); document.write( " |