document.write( "Question 175156: Find two consecutive integers such that four times the larger exceeds three times the smaller by 23.
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Algebra.Com's Answer #130230 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
Call the smaller integer $\"n\"$
\n" ); document.write( "The next larger integer is $\"n%2B1\"$
\n" ); document.write( " $\"4%28n%2B1%29+=+3n+%2B+23\"$
\n" ); document.write( " $\"4n+%2B+4+=+3n+%2B+23\"$
\n" ); document.write( " $\"n+=+19\"$
\n" ); document.write( " $\"n%2B1+=+20\"$
\n" ); document.write( "The numbers are 19 and 20
\n" ); document.write( "check:
\n" ); document.write( " $\"4%28n%2B1%29+=+3n+%2B+23\"$
\n" ); document.write( " $\"4%2A20+=+3%2A19+%2B+23\"$
\n" ); document.write( " $\"80+=+57+%2B+23\"$
\n" ); document.write( " $\"80+=+80\"$
\n" ); document.write( "OK \n" ); document.write( "

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