document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=24348>Question 24348</A>: <I><SPAN STYLE=\"word-break: break-all;\"> -2y-3(y+1) = -(5y+3)+ y\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #13023 by </B><A HREF=/tutors/aboutme.mpl?userid=yhtong><B>yhtong(11)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=yhtong><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=13023\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> first, solve all that you can solve,<BR>\n" );
document.write( "-2y-3(y+1) = -(5y+3)+ y<BR>\n" );
document.write( "-2y-3y-3   =-5y-3+y<BR>\n" );
document.write( "-5y-3      =-4y-3\r<BR>\n" );
document.write( "\n" );
document.write( "Bring the unknown to the left hand side(LHS), then, the numbers to the right hand side(RHS)<BR>\n" );
document.write( "-5y+4y=-3+3<BR>\n" );
document.write( "     y=0\r<BR>\n" );
document.write( "\n" );
document.write( "therefore, y=0\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );