document.write( "Question 175148: How do I solve the equation for x: 64=2^3^x? \n" ); document.write( "
Algebra.Com's Answer #130222 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
I think you mean: \"64=2%5E3%5Ex\"\r
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\n" ); document.write( "\n" ); document.write( "Recognize that 64 is a power of 2, namely \"64=2%5E6\". Hence, \"2%5E6=2%5E3%5Ex\" and therefore \"3%5Ex=6\"\r
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\n" ); document.write( "\n" ); document.write( "Take the log of both sides:\r
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\n" ); document.write( "\n" ); document.write( "\"log%28%283%5Ex%29%29=log%28%286%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "But we know that \"log%28%28r%5Es%29%29=s%2Alog%28%28r%29%29\", so:\r
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\n" ); document.write( "\n" ); document.write( "\"x%2Alog%28%283%29%29=log%28%286%29%29\" and finally,\r
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\n" ); document.write( "\n" ); document.write( "\"x=log%28%286%29%29%2Flog%28%283%29%29\" which is the exact answer. Use your calculator for a numerical approximation of the appropriate precision if necessary.
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