document.write( "Question 175061: The difference between two positive numbers is 4 .If twice the number is added to three times the smaller ,the sum is 53.Which are the steps to the solution? \n" ); document.write( "

Algebra.Com's Answer #130156 by Mathtut(3670) $\"\"$ $\"About$

You can put this solution on YOUR website!
first read the problem carefully:
\n" ); document.write( "next, turn this from a word problem to an equation or system of equations
\n" ); document.write( ":
\n" ); document.write( "we have 2 unknown numbers lets call them a and b
\n" ); document.write( "the difference(we know subtraction is involved here) between 2 postive numbers(a and b) equals 4...so a-b=4. In this next sentence they are distinguishing these numbers as smaller and larger. From the first equation we know in our case, that a is the larger and b the smaller. twice(2a)is added to(+3b) equals 53. so we have 2 equations
\n" ); document.write( ":
\n" ); document.write( "a-b=4.....eq 1
\n" ); document.write( "2a+3b=53..eq 2
\n" ); document.write( ":
\n" ); document.write( "now lets solve. Re write eq 1 to a=4+b and take a's value of 4+b and plug it into eq 2
\n" ); document.write( ":
\n" ); document.write( "2(4+b)+3b=53
\n" ); document.write( ":
\n" ); document.write( "8+2b+3b=53
\n" ); document.write( ":
\n" ); document.write( "5b=45
\n" ); document.write( ":
\n" ); document.write( " $\"highlight%28b=9%29\"$
\n" ); document.write( ":
\n" ); document.write( " $\"highlight%28a=4%2Bb=4%2B9=13%29\"$
\n" ); document.write( ":
\n" ); document.write( " \n" ); document.write( "

\n" );